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对于使用二维数组的每个循环

[英]For each loop using 2D array

This is the snippet of Java code:这是 Java 代码的片段:

int[][] uu = new int[1][1];
uu[0][0] = 5;
for(int[] u: uu){
    System.out.println(u[0]);
}

It prints 5. But why does the declaration part of for loop is declared as int[] u , but not as int[][] u ?它打印 5。但是为什么 for 循环的声明部分被声明as int[] u ,而不是as int[][] u

At the uu you reference 2D array... That is not a homework.在 uu 你引用 2D 数组......那不是作业。 I am preparing for Java certification.我正在准备Java认证。 Cheers干杯

Since your uu is an array of array . 因为你的uu是一个array of array So, when you iterate over it, you will first get an array , and then you can iterate over that array to get individual elements. 因此,当您迭代它时,您将首先获得一个array ,然后您可以迭代该数组以获取单个元素。

So, your outer loop has int[] as type, and hence that declaration. 所以,你的外部循环有int[]作为类型,因此声明。 If you iterate through your u in one more inner loop, you will get the type int : - 如果你在另一个内部循环中遍历你的u ,你会得到int类型: -

for (int[] u: uu) {
    for (int elem: u) {
        // Your individual element
    }
}

It is because uu is an array of int[] arrays. 这是因为uu是一个int[]数组的数组。 So every item in it is int[] . 所以其中的每一项都是int[] In a for loop you declare the type of an item in an array you iterate over. for循环中,您声明迭代的数组中项的类型。

The loop is iterating on the elements of uu , which are objects of type int[] . 循环迭代uu的元素,它们是int[]类型的对象。 (Or in other words - u is an element in uu , thus it is an int[] ). (换句话说 - uuu的元素,因此它是int[] )。

The declaration is always of the type of the objects retrieved by the iteration - in this case - it is int[] - 声明始终是迭代检索的对象的类型 - 在这种情况下 - 它是int[] -

Same as iterating over an int[] is: 与迭代int[]是:

 for (int x : myArray) { ...}

because each element of x is of type int . 因为x每个元素都是int类型。

"why does the declaration part of for loop is declared as int[] u, but not as int[][] u?" “为什么for循环的声明部分被声明为int [] u,而不是int [] [] u?”

The array is two-dimensional, so you are dealing with a double-layered iteration. 该数组是二维的,因此您正在处理双层迭代。 You have an array "inside" another, in the same principle as List<List<Integer>> would work. 你有一个“内部”数组,其原理与List<List<Integer>>相同。

To iterate through all the elements, you should consider a rows-elements structure. 要遍历所有元素,您应该考虑行元素结构。 It's necessary that you get each row from the container, and then each element from each row. 您必须从容器中获取每一行,然后从每行获取每个元素。

for(int[] u: uu) is simply a for-each iteration rows, with the same principle of for(int row = 0; row < container.length; row++) , and u or respectively container[row] are not elements themselves, but rows (arrays) of elements. for(int[] u: uu)只是for-each迭代行,其原理与for(int row = 0; row < container.length; row++) ,而u或者container[row]都不是元素他们自己,但元素的行(数组)。 Meaning you require a second iteration layer to get the elements: 这意味着您需要第二个迭代层来获取元素:

int[][] container = new int[10][10];
//... - Fill elements.
for(int row = 0; row < container.length; row++){
  for(int element = 0; element < container[row].length; element++){
    System.out.printf("Row: %d Element: %d Value: %d\n", row, element, container[row][element]);
  }
}

This is an example of finding the sum in 2d array and print it这是在二维数组中查找总和并打印它的示例

public class Array2DForEach {
    public static void main(String[] args) {
        int sum = 0;
        int[][] myFirst2DArray = {
                                    { 3, 5, 1, 9 },
                                    { 10, 15, 3, 0  },
                                    { 1, 11, 31, 90 },
                                    { 2, 51, 1, 9 }
                                };

        for (int[] row:myFirst2DArray) {

            for (int columnElement : row) {
                sum+=columnElement;
            }
            
        }
        System.out.println(sum);
    }
}

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