轮廓的x，y轴长度的计算

Question

Good day everybody.

I am still working with the same old program and so far I managed to find the area and the coordinate of the biggest contour based on calculation of the contour's moments.

double m_00 = cvGetSpatialMoment( &moments, 0, 0 ); //The area
double m_10 = cvGetSpatialMoment( &moments, 1, 0 );
double m_01 = cvGetSpatialMoment( &moments, 0, 1 );
float gravityX = (m_10 / m_00);     //center of x-axis              
float gravityY = (m_01 / m_00);     //center of y-axis

...and what I get is this:

...which is working nicely. But now I want to get the length of x-axis and y-axis of the contour/object, which is something like this:

The question is is there any function that can calculate the x-axis and y-axis length of the contour? If so, can anyone kindly give me some clue how to do it?

Thanks in advance. Cheers.

P/S: The program I linked above is the old one so it has some error in it.

Answer 1

After I spend almost a day went around googling for the answer, I finally found an alternative way to get the width and the height of the object, which is by using cvBoundingRect function. Basically it will make an upright bounding rectangle around the contour, so I just need to retrieve the width and the height of the box to get what I want.

The code:

    Rect rect= cvBoundingRect(contour,0);
    double pt1, pt2;
    pt1 =rect.width;      //width
    pt2 =rect.height;     //heigth

BTW thanks for all your help. Cheers.