使用xslt将一个xml的内容复制到另一个

Question

I am trying to copy a content from one xml to other xml using Xslt.

I need to copy content of file1

<?xml version="1.0"?>
<products author="Jesper">
  <product>
    <name>Delta</name>
    <price>800</price>
    <stock>
        <price>13a</price>
    </stock>
    <place>Denmark</place>
  </product>
</products>

to file 2. File2 has similar tags but order is jumbled,

<?xml version="1.0"?>
<products author="Jesper">
  <product>
    <stock>
        <price>13d</price>
    </stock>
    <price>700</price>
    <place>Copenhagen</place>
     <name>Beta</name>
  </product>
</products>

expected output

<products author="Jesper">
  <product>
    <stock>
        <price>13a</price>
    </stock>
    <price>800</price>
    <place>Denmark</place>
     <name>Delta</name>
  </product>
</products>

so basically I need to Iterate through file1 using for-each and then find the matching tag in file2 and copy the tag value. Not sure about an efficient way to do so ... Double iterating is inefficient. Any suggestion will be helpful.

Answer 1

This is a very broad question, but I'll try to give you some pointers that should get you started. You will probably want to use the doc() function to load the files since XSLT only allows you to iterate over a single "main" file. doc() loads a new file into a variable that you can apply templates to and so on. If you are concerned about the iteration performance, you should learn about xsl:key and the key() function, which build indexes that will help with that.