Passing an array as an argument to a function pointer in C

Question

I'm currently studying pointers to functions and have been practicing on sort array functions. The point is I input a sequence of numbers into the function and the program will re arrange it in ascending order. It worked just fine when I do a call by value function (I think that's how you call it). However when I try to assign a pointer to function and try to use that pointer instead of the function itself, it returns a bunch of errors. I'm sure the problem is due to the fact that I'm passing an array as an argument to the function POINTER. Here is my code:

#include<stdio.h>
#define SIZE 10

void sort(int a[], int size);
void swap(int *elt1, int *elt2);
main()
{
    int i; int array[SIZE]= {1,9,3,2,4,100,43,23,32,12};
    void (*fptr)(int array, int SIZE);
    fptr = &sort;
    (*fptr)(array,SIZE);
    /*sort(array, SIZE);*/
    for(i=0;i<SIZE;i++)
    {
            printf("%d\n", array[i]);
    }
    return 0;
}

void sort(int a[], int size)
{
    int pass, j;
    for(pass = 0; pass<size;pass++)
    {
            for(j=0;j<size;j++)
            {
                    if(a[j]>a[j+1])
                    {
                            swap(&a[j], &a[j+1]);
                    }
            }

    }


}


void swap(int *elt1, int *elt2)
{
    int hold;
    hold = *elt1;
    *elt1 = *elt2;
    *elt2 = hold;

}

Answer 1

The first argument of the function is a pointer to int (that is, int * ), and not int .

void (*fptr)(int array, int SIZE);

should be

void (*fptr)(int *array, int SIZE);