I have two arrays. How can I join them into one multidimensional array?
The first array is:
var arrayA = ['Jhon, kend, 12, 62626262662',
'Lisa, Ann, 43, 672536452',
'Sophie, Lynn, 23, 636366363'];
My other array has the values:
var arrayB = ['Jhon', 'Lisa', 'Sophie'];
How could I get an array with this format??
var jarray = [['Jhon', ['Jhon, kend, 12, 62626262662']],
['Lisa', ['Lisa, Ann, 43, 672536452']],
['Sohphie', ['Sophie, Lynn, 23, 636366363']]]
var jarray = [];
for (var i=0; i<arrayA.length && i<arrayB.length; i++)
jarray[i] = [arrayB[i], [arrayA[i]]];
However, I wouldn't call that "multidimensional array" - that usually refers to arrays that include items of the same type. Also I'm not sure why you want the second part of your arrays be an one-element array.
Here is a map version
var arrayA = ['Jhon, kend, 12, 62626262662', 'Lisa, Ann, 43, 672536452', 'Sophie, Lynn, 23, 636366363']; var arrayB = ['Jhon', 'Lisa', 'Sophie']; /* expected output var jarray = [['Jhon', ['Jhon, kend, 12, 62626262662']], ['Lisa', ['Lisa, Ann, 43, 672536452']], ['Sohphie', ['Sophie, Lynn, 23, 636366363']]] */ var jarray = arrayB.map(function(item,i) { return [item,[arrayA[i]]]; }); console.log(jarray);
You can use Underscore.js http://underscorejs.org/#find Looks through each value in the list, returning the first one that passes a truth test (iterator). The function returns as soon as it finds an acceptable element, and doesn't traverse the entire list.
var even = _.find([1, 2, 3, 4, 5, 6], function(num){ return num % 2 == 0; });
=> 2
Then, you can make the same with the array B elements and by code, make a join.
This is what I did to get what you were asking:
var jarray = [];
for (var i = 0; i < arrayB.length; i++) {
jarray[i] = [];
jarray[i].push(arrayB[i]);
var valuesList = [],
comparator = new RegExp(arrayB[i]);
for (var e = 0; e < arrayA.length; e++) {
if (comparator.test(arrayA[e])) {
valuesList.push(arrayA[e]);
}
}
jarray[i].push(valuesList);
}
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