shell script not running the other script inside it

Question

#!/bin/bash
value=$(</var/www/sym_monitor/man.txt)


if [ "$value" == "true" ]; then

     ps -ef|grep sym |grep -v grep |awk '{ print $2 }'|sudo  xargs kill -9;
cd /var/www/symmetric-ds-3.1.6/bin;
sleep 30;

(sudo ./sym --port 8082 --server);

fi

I'm trying to run the above script every 10 mins using cron. While running it under root manually the script is doing fine but when I try to run the script inside cron it is executing the (ps -ef|grep sym |grep -v grep |awk '{ print $2 }'|sudo xargs kill -9;) and it is not executing the script (sudo ./sym --port 8082 --server) and it is not giving any error. Can anybody suggest me any idea?

Answer 1

Please check if crontab is also running in Bash. If not then you might have have to change your shell.

Also when you are running the script manually, ./sym is a location pertaining to your shell. It might not be as per cron. Please use full path to execute ./sym.

Answer 2

sudo may require a password, thus blocking this command.

Removing sudo would solve the problem, I guess.