I am trying to code gauss elimination and this is the piece of code I'm using. The matrix is already triangular but there is a mistake in this expression:
x(n) = b(n) / A(n, n);
Here is the complete piece of code:
function [x] = gauss(A, b)
n = size(A);
for k=1 : n-1
for i=k+1 : n
m = A(i, k) / A(k, k);
for j=1 : n
A(i, j) = A(i, j) - m * A(k, j);
end
b(i) = b(i) - m * b(k);
end
end
x(n) = b(n) / A(n, n);
disp(double(b(n)));
for k=n-1 : -1 : 1
s=0;
for i=k+1 : n
s = s + A(k, i) * x(i);
end
x(k) = (b(k) - s) / A(k, k);
end
disp(x);
end
Thanks for your help. BTW Im a newbie in Matlab...
Edit: adding some more info
Im calling this function like this: A = [6 3 2 ; 9 -1 4 ; 10 5 3] b = [12 37 21]
sol = gauss(A, b);
This line
n = size(A);
will have a vector result as A
is a matrix. It appears that you are expecting this line
x(n) = b(n) / A(n, n);
to behave like a scalar division, but with n
a vector you are actually trying to divide matrices of different dimension. Based on your example code examine the output of these statements
n = size(A);
A(n,n)
b(n)
and see that you are not dealing with scalars. If you want n
to be a scalar equal to the number of rows of A
try replacing
n = size(A);
with
[n n1] = size(A);
and now n
should truly represent the row count of A
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.