the array[time, value];
I need to total/sum of value from this two dimensional array?
var array =[
[1361824790262, 90.48603343963623],
[1361828390262, 500.18687307834625],
[1361831990262, 296.05108177661896],
[1361835590262, 423.1198309659958],
[1361839190262, 11.86623752117157],
[1361842790262, 296.38282561302185],
[1361846390262, 424.31847417354584],
[1361849990262, 100.07041704654694],
[1361853590262, 434.8605388402939],
[1361857190262, 434.8220944404602],
[1361860790262, 183.61854946613312]
];
var sum = 0;
//console.log(array.length);
for (var i = 0; i < array.length; i++) {
//console.log(array[i]);
for (var j = 0; j < array[i].length; j++) {
console.log(array[j][i]);
sum += array[j][i];
}
}
console.log(sum);
Your question title implies you want to sum a two dimensional array—here's how you would do that:
array.reduce(function(a,b) { return a.concat(b) }) // flatten array
.reduce(function(a,b) { return a + b }); // sum
To sum only the value portions as you made clear in your edit is even easier:
array.map(function(v) { return v[1] }) // second value of each
.reduce(function(a,b) { return a + b }); // sum
There's no need for two loops. This loops through the array and gives you each time/value pair. Simply sum the first index (second item) if each time-value pair.
var sum = 0;
for(var i=0;i<array.length;i++){
console.log(array[i]);
sum += array[i][1];
}
console.log(sum);
Output:
[1361824790262, 90.48603343963623]
[1361828390262, 500.18687307834625]
[1361831990262, 296.05108177661896]
[1361835590262, 423.1198309659958]
[1361839190262, 11.86623752117157]
[1361842790262, 296.38282561302185]
[1361846390262, 424.31847417354584]
[1361849990262, 100.07041704654694]
[1361853590262, 434.8605388402939]
[1361857190262, 434.8220944404602]
[1361860790262, 183.61854946613312]
3195.7829563617706
Sum_of_2d_array(arr)
{
int sum_time =0;
int sum_value=0;
for(i=0;i<arr.length;i++)
{
sum_time = sum_time + arr[i,0];
}
print(sum_time);
for(i=0;i<arr.length;i++)
{
sum_value = sum_value + arr[i,1];
}
print(sum_value);
}
If I understood your question correctly. I think this is what you want.
var arr = [[1361824790262, 90.48603343963623],
[1361828390262, 500.18687307834625],
[1361831990262, 296.05108177661896],
[1361835590262, 423.1198309659958],
[1361839190262, 11.86623752117157],
[1361842790262, 296.38282561302185],
[1361846390262, 424.31847417354584],
[1361849990262, 100.07041704654694],
[1361853590262, 434.8605388402939],
[1361857190262, 434.8220944404602],
[1361860790262, 183.61854946613312]];
var sum = 0;
for(var i=0;i<arr.length;i++){
for(var j=0;j<arr[i].length;j++){
sum += arr[i][j];
}
}
console.log(sum);
This is the solution for get the total. I have test it.
function sum(array) {
let sum = 0
for (let i = 0; i < array.length; i++) {
for (let j = 0; j < array[i].length; j++) {
sum = sum + array[i][j]
}
}
return sum
}
console.log(
sum([
[1, 1],
[2, 2],
[5, 5],
])
) //22
That's It:) Have a Good day!
const array2d = [[1, 2], [3, 4]];
array2d.flat().reduce((sum, currentValue) => sum + currentValue); // 10
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