Scandir: Checking for files with the same name (excluding extension)

Question

Is it possible to check for files with the same file name (which only differ in the file extension) and only display their names once?

if (is_dir($dir_path)) {

    $files = scandir($dir_path);

    foreach($files as $file) {

        if ( !in_array( $file, $exclude_all ) ) {

            $path_to_file = $dir_path . $file;
            $bare_name = pathinfo( $path_to_file, PATHINFO_FILENAME );
            $extension = pathinfo( $path_to_file, PATHINFO_EXTENSION );

            echo 'Path to file: ' . $path_to_file . '<br />';
            echo 'Bare file name: ' . $bare_name . '<br />';
            echo 'Extension: ' . $extension . '<br />';         

        }
    }
}

Answer 1

you can try this:

//first save all files in an array
$bare_name = pathinfo( $path_to_file, PATHINFO_FILENAME );
if(!in_array($bare_name, $files)){
 $files[] = $bare_name;
}

Now $files contains unique filename

Answer 2

Try this

if (is_dir($dir_path)) {

$tmpBareNames = array();

$files = scandir($dir_path);

foreach($files as $file) {

    if ( !in_array( $file, $exclude_all ) ) {

        $path_to_file = $dir_path . $file;
        $bare_name = pathinfo( $path_to_file, PATHINFO_FILENAME );
        if(!in_array($bare_name,$tmpBareNames))
            $tmpBareName[] = $bare_name;
        else break;
        $extension = pathinfo( $path_to_file, PATHINFO_EXTENSION );

        echo 'Path to file: ' . $path_to_file . '<br />';
        echo 'Bare file name: ' . $bare_name . '<br />';
        echo 'Extension: ' . $extension . '<br />';         

    }
}
}