I have a directory filled with multiple .c source files and I am trying to write a shell script in another directory that will copy the first .c file from the previous directory, compile it, run it, and delete it. Now I understand how to compile, run, and delete the files but I am stumped as to how get only one .c file without knowing its name when there are multiple files with the same extension in the directory?
One way is to use a loop, then break out after the first iteration:
for f in dir/*.c; do
cp "$f" .
# compile
# run
# delete
break
done
You haven't specified how you define "the first", but you can use set
for this:
set -- source_dir/*.c
cp "$1" .
# ...
rm "$1"
Assuming that you by "first" mean the first file in a sorted list.
A for loop works fine, but you could also do:
file=`ls -1 dir/*.c | head -1`
# compile $file && run $file && delete $file
In bash you can use arrays:
files=(*.c)
echo "compiling ${files[0]}"
compile ${files[0]}
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