I am currently writing program to communicate with a device in my network, and the following code is what I have so far, it passed authentication and can get the webpage from the device, however i couldnt get the GET request to work, when I run the code below, i get the error:
Exception in thread "main" java.io.FileNotFoundException: http://192.168.100.222:80
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
when I input data on the webpage, its equivalent of going http://l192.168.xxx.xxx/2?A=3&p=1&X=1234 , and from tcpflow, it does GET /2?A=4&p=1&X=1234 HTTP/1.1
, I tried creating a new url connection with http://192.168.xxx.xxx/2?A=3&p=1&X=1234 , and it worked, but i have multiple input options and i dont want to create a new connection for each of them, how can I do the equivalent while staying connected? or what I did wrong in the code?
thanks in advance.
public class main {
public static void main(String[] argv) throws Exception {
Authenticator.setDefault(new MyAuthenticator());
URL url = new URL("http://192.168.xxx.xxx");
URLConnection connection = url.openConnection();
connection.setDoOutput(true);
connection.setDoInput(true);
OutputStreamWriter out = new OutputStreamWriter(connection.getOutputStream());
out.write("Get /2?A=4&p=1&X=1234 HTTP1.1");
out.close();
BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String decodedString;
while ((decodedString = in.readLine()) != null) {
System.out.println(decodedString);
}
in.close();
}
I don't want to create a new connection for each of them
Don't worry about that. HttpURLConnection
does connection pooling under the hood. Just use your actual URLs, don't try to out-think Java.
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