How to assign a filename with a pointer one?

Question

I do have a function that I have created with a pointer as an argument. That argument will be used to save at the end an image. Every time when I would like to call that function with the desired parameter, I want that the saved image file would be with the specified name. I show you how:

void SaveImage(IplImage *img)
{
...
cvSaveImage("C:/img.png", img);
...
}

when calling the function: SaveImage(image1), I want to have an image on my C:/ whose name is image.png

Can you help me with that?

Answer 1

Apparently, you can't answer this question with the only answer that is actually viable, because you get downvoted...

So, I'll rephrase my answer:

You need to pass two variables to SaveImage:

void SaveImage(const char *name, IplImage *img)
{
   ...
   cvSameImage(name, img);
}

Then your calling code will have to produce the correct name, such as:

SaveImage("c:\image.png", image);

SaveImage("c:\other.png", other);

Now, of course, if all you actually want is a unique name, rather than one that reflects the name of the variable in your code, then there are plenty of other possibilities, such as using a formatted string that contains a serial number, a random number, tmpnam() or other similar schemes.

Answer 2

As I understand, you want save the file with the name of passed object.

For example, after SaveImage(myImage); it should save the image with name myImage.png , am I right? Well. It's impossible since C++ hasn't such a reflection to retrieve object's name. You should try some dirty jobs, using MACROs to stringify the object.

BUT, If you want save images in different names, you can use a static variable:

void SaveImage(IplImage *img)
{
...
static int num = 1;
cvSaveImage("C:/image"+ to_string(num++) +".png", img);
...
}