C# XML serializing with attributes for every element

Question

I want to create the following xml:

 <StartLot>
      <fileCreationDate level="7">201301132210</fileCreationDate>
      <fmtVersion level="7">3.0</fmtVersion>
 </StartLot>

Below is the Serialization code:

[Serializable]
class StartLot
{
    public fileCreationDate{get; set;}

    [XmlAttribute("level")] 
    public string level = "7";

    public fmtVersion{get; set;}

    [XmlAttribute("level")] 
    public string level = "7"; ??
}

Since I already declared attribute level, how do I add the last attribute?

Answer 1

You can use a wrapped class to store both values, as in the example below:

public class StackOverflow_15441384
{
    const string XML = @"<StartLot>
                               <fileCreationDate level=""7"">201301132210</fileCreationDate>
                               <fmtVersion level=""7"">3.0</fmtVersion>
                            </StartLot>";
    public class StartLot
    {
        [XmlElement("fileCreationDate")]
        public LevelAndValue FileCreationDate { get; set; }
        [XmlElement("fmtVersion")]
        public LevelAndValue FmtVersion { get; set; }
    }
    public class LevelAndValue
    {
        [XmlAttribute("level")]
        public string Level { get; set; }
        [XmlText]
        public string Value { get; set; }
    }
    public static void Test()
    {
        XmlSerializer xs = new XmlSerializer(typeof(StartLot));
        StartLot sl = (StartLot)xs.Deserialize(new MemoryStream(Encoding.UTF8.GetBytes(XML)));
        Console.WriteLine("FCD.L = {0}", sl.FileCreationDate.Level);
        Console.WriteLine("FCD.V = {0}", sl.FileCreationDate.Value);
        Console.WriteLine("FV.L = {0}", sl.FmtVersion.Level);
        Console.WriteLine("FV.V = {0}", sl.FmtVersion.Value);
    }
}

Answer 2

I always find Linq To Xml easier to use

var xDoc = XDocument.Parse(xml); /* XDocument.Load(filename); */

var items = xDoc.Root.Descendants()
                .Select(e => new
                {
                    Name = e.Name.LocalName,
                    Level = e.Attribute("level").Value,
                    Value = e.Value
                })
                .ToList();