handling arguments in Lua function with variable number of arguments

Question

I was trying to write a function with a variable number of arguments which do something for all its number entries. so I came up with something like this:

function luaFunc (...)
   for i,v in ipairs{...} do
      if type(v)=='number' then
         --do something
      end
   end
end

but when i run this, it stops right on first non-number argument. whats the problem?

Answer 1

local function luaFunc (...)
   for i = 1, select('#',...) do
      local v = select(i,...)
      if type(v)=='number' then
         --do something
         print(v)
      end
   end
end
luaFunc (1,'a',nil,2)     ]

-- Output
1
2

Answer 2

Try also this:

function luaFunc (...)
   local t=table.pack(...)
   for i=1,t.n do
      local v=t[i]
      if type(v)=='number' then
         print(i,v)
      end
   end
end

luaFunc(10,20,"hello",40,nil,60,print,99)