I have dictionary like this:
{
'28.10.11/D/text1/' : {key:value1},
'27.01.11/D/text2/' : {key:value2},
'07.11.12/D/text3/' : {key:value3}
}
Part of the key is based on the date, that set in "%d.%m.%Y" format. Need to sort all the dictionary keys by date. Value must be saved in the same format. Example:
{
'27.01.11/D/text2/' : {key:value2},
'28.10.11/D/text1/' : {key:value1},
'07.11.12/D/text3/' : {key:value3}
}
You can't sort a standard dictionary, but you can sort and display the items.
from datetime import datetime
D = {'28.10.11/D/text1/' : {'key':'value1'},
'27.01.11/D/text2/' : {'key':'value2'},
'07.11.12/D/text3/' : {'key':'value3'}}
for k in sorted(D,key=lambda k: datetime.strptime(k[:8],"%d.%m.%y")):
print(k,D[k])
Output:
27.01.11/D/text2/ {'key': 'value2'}
28.10.11/D/text1/ {'key': 'value1'}
07.11.12/D/text3/ {'key': 'value3'}
If you want to use a list:
from datetime import datetime
from pprint import pprint
L = [('28.10.11/D/text1/' , {'key':'value1'}),
('27.01.11/D/text2/' , {'key':'value2'}),
('07.11.12/D/text3/' , {'key':'value3'})]
L.sort(key=lambda k: datetime.strptime(k[0][:8],"%d.%m.%y"))
pprint(L)
Output:
[('27.01.11/D/text2/', {'key': 'value2'}),
('28.10.11/D/text1/', {'key': 'value1'}),
('07.11.12/D/text3/', {'key': 'value3'})]
Finally if you still want dictionary behavior, an OrderedDict remembers the order keys are inserted, so:
from collections import OrderedDict
from datetime import datetime
from pprint import pprint
D = {'28.10.11/D/text1/' : {'key':'value1'},
'27.01.11/D/text2/' : {'key':'value2'},
'07.11.12/D/text3/' : {'key':'value3'}}
OD = OrderedDict(sorted(D.items(),
key=lambda k: datetime.strptime(k[0][:8],"%d.%m.%y"))
pprint(OD)
Output:
{'27.01.11/D/text2/': {'key': 'value2'},
'28.10.11/D/text1/': {'key': 'value1'},
'07.11.12/D/text3/': {'key': 'value3'}}
Use sorted
function with key
argument. Write key
function that converts string to a Datetime
, and sort based on the Datetime
.
def remap_key(key):
from datetime import datetime
a = key.split('/')[0]
return datetime.strptime(a, "%d.%m.%y")
>>> d = {
... '27.01.11/D/text2/' : "a",
... '28.10.11/D/text1/' : "b",
... '07.11.12/D/text3/' : "c"
... }
>>>
>>> def remap_key(key):
... from datetime import datetime
... a = key.split('/')[0]
... return datetime.strptime(a, "%d.%m.%y")
...
>>> sorted(d, key=remap_key)
['27.01.11/D/text2/', '28.10.11/D/text1/', '07.11.12/D/text3/']
Or sort on iteritems
:
>>> def remap_key(key_pair):
... from datetime import datetime
... key = key_pair[0]
... a = key.split('/')[0]
... return datetime.strptime(a, "%d.%m.%y")
...
>>> sorted(d.iteritems(), key=remap_key)
[('27.01.11/D/text2/', 'a'), ('28.10.11/D/text1/', 'b'), ('07.11.12/D/text3/', 'c')]
As another option, you can use OrderedDict in combination with datetime (as mentioned by hughdbrown):
>>> from collections import OrderedDict
>>> from datetime import datetime
>>> d = {
'28.10.11/D/text1/' : {'key1':'value1'},
'27.01.11/D/text2/' : {'key2':'value2'},
'07.11.12/D/text3/' : {'key3':'value3'}
}
>>> OrderedDict(sorted(d.items(), key=lambda t: datetime.strptime(t[0][:8], "%d.%m.%y")))
The result:
OrderedDict([('27.01.11/D/text2/', {'key2': 'value2'}), ('28.10.11/D/text1/', {'key1': 'value1'}), ('07.11.12/D/text3/', {'key3': 'value3'})])
You'll get precisely the order you are looking for, and each part of the date will be compared to corresponding parts of other dates in a regular fashion.
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