get distinct value count in mysql select query

Question

I have one table in MySQL as below.

id | number | name | type

111 | 123 | XYZ | bar

222 | 234 | ABC | restaurants

111 | 007 | PKA | food

111 | 123 | XYZ | bar

333 | 123 | XYZ | bar

Now what I would like to get is total size of number which is having unique id. Meaning in my case 111 and 333 have same number that is 123 . So the total count for number 123 is 2. Here I don't want to count 111 again as you can see that 111 came twice for the number 123 but I don't want to add it in the total size as its already there in the count. So i want the unique id's count which is having same number.

OUTPUT i want from the query is :-

123 (XYZ) - 2 (There are total 3 entry but 111 id is repeated for number 123 and I don't want duplicated one. So I want to take both id and number in consideration while getting the count.)

234 (ABC) - 1

007 (PKA) - 1

I used the Group By for finding duplicate values but didn't get the proper output as per my requirements. Any help or suggestions would be welcomed.

Answer 1

select number, count(distinct id)
from your_table
group by number

Answer 2

also possible:

select id, number, name, type, 
       count(distinct id) over (partition by number) numOfDistictIds
from table
order by number