I'm looking over replace()
examples and I'm not exactly sure the best way to do this:
Say I have a string something like
{G}{J}{L}...
What's the best way to use string.replace()
to change the inner and outer brackets but leave the letter inside them? Do I need to do separate matches for the outer and inner brackets or is it possible/faster to do it in a single statement?
I see that $
can get the whole match and I guess I could remove the first and last characters and replace them after but that seems slow.
> "{G}{J}{L}".replace(/{(.)}/g,"$1")
"GJL"
Is this what you're after? Or maybe this?
> "{G}{J}{L}".replace(/{(.)}/g,"[$1]")
"[G][J][L]"
One pretty straightforward way is to just perform the replacements separately, and the performance difference should be negligible unless your strings are huge:
var string = "{G}{J}{L}";
string = string.replace(/\{/g, "<").replace(/}/g, ">")
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