Jersey Exception

Question

Does anyone know what this exception means? I'm using GWT - Java 1.7.

Here the console output:

[WARN] failed jersey-servlet
javax.servlet.ServletException: com.sun.jersey.spi.inject.Errors$ErrorMessagesException
at org.mortbay.jetty.servlet.ServletHolder.initServlet(ServletHolder.java:437)
at org.mortbay.jetty.servlet.ServletHolder.doStart(ServletHolder.java:256)
...

Here's the web.xml:

<servlet>
  <servlet-name>jersey-servlet</servlet-name>
  <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
  <init-param>
     <param-name>com.sun.jersey.config.property.packages</param-name>
     <param-value>de.mme2app.open.server, org.codehaus.jackson.jaxrs</param-value>
  </init-param>
  <init-param>
     <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
     <param-value>true</param-value>
  </init-param>
  <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
  <servlet-name>jersey-servlet</servlet-name>
  <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

Answer 1

I haven't verified that this is causing that error specifically, but the com.sun.jersey.config.property.packages param should just point to packages containing your resources and providers. It doesn't seem like org.codehaus.jackson.jaxrs belongs there. Try it will just:

<init-param>
    <param-name>com.sun.jersey.config.property.packages</param-name>
    <param-value>de.mme2app.open.server</param-value>
</init-param>

Assuming de.mme2app.open.server is the package in your project with resources/providers.