I have a function void displayList() that displays a list of a set. in the main function I also have
ofstream outputFile(output.txt)
how do I call displayList and prints it in output.txt? Thanks.
displaylist is just some bunch of cout lines
Let's assume your DisplayList is currently something like:
void DisplayList() {
cout << "a" << a << "\n";
}
I would rewrite it to become two overloaded functions:
void DisplayList(std::ostream &os) {
os << "a" << a << "\n";
}
void DisplayList() { DisplayList(std::cout); }
Then your existing code can continue to call DisplayList()
with no parameters and get the current behavior. Code that wants to specify the destination file instead, can call:
Displaylist(outputFile);
And the output will got to the file they specified instead of cout
.
This could be done as a function with a default argument instead, but under the circumstances, I think a pair of overloaded functions is probably simpler.
我相信是:
outputFile << displayList();
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