Select Count of ip and Count of DISTINCT ip in same query

Question

I have a table structure like this:

TABLE NAME : counter

id  |        datetime       |  url  | ip
-------------------------------------------
1   |2013-04-12 13:27:09    | url1  | ip01
2   |2013-04-13 10:55:43    | url2  | ip02
3   |2013-04-14 11:14:12    | url1  | ip03
4   |2013-04-15 23:23:55    | url2  | ip04
5   |2013-05-02 08:34:44    | url1  | ip03

With a smart SELECT query, I want to fetch 3 columns that are:

Distinct URL    |    count of ip            |    count of distinct ip
                |    for each distinct url  |    for each distinct url  
-------------------------------------------------------------------
url1            |    3                      |    2    
url2            |    2                      |    2

I came up with my query below by the help of this solution in stackoverflow which gives me the first 2 columns that I need:

SELECT url, COUNT(*) AS total_ip FROM counter GROUP BY url ORDER BY total_ip DESC

But how can I add the 3rd column also into my query?

Can you please help me?

Answer 1

As you mentioned yourself, you can use DISTINCT keyword to get distinct URL s. Use COUNT to get count of IP and COUNT(DISTINCT ID) to get distinct IP for each URL s

Try this:

SELECT DISTINCT URL AS D_URL
      ,COUNT(IP) AS IP
      ,COUNT(DISTINCT IP) AS D_IP
FROM counter
GROUP BY URL

Output:

╔═══════╦════╦══════╗
║ D_URL ║ IP ║ D_IP ║
╠═══════╬════╬══════╣
║ url1  ║  3 ║    2 ║
║ url2  ║  2 ║    2 ║
╚═══════╩════╩══════╝

See this SQLFiddle