Convert from raw pointers to smart pointers

Question

I want to use smart pointers instead of raw pointers. How can I convert this function accordingly?

Node * List::next(const Node * n) const {
    return n->next;
}

Answer 1

Like this:

Node * List::next(const Node * n) const {
    return n->next;
}

As far as I can tell the function next doesn't not perform any transfer of ownership so it doesn't need to concern itself with means of ownership of Node objects so it doesn't need to change. (It doesn't need to be a member of List or it could be a static member.)