Matching a Forward Slash with a regex

Question

I don't have much experience with JavaScript but i'm trying to create a tag system which, instead of using @ or # , would use / .

var start = /#/ig; // @ Match

var word = /#(\w+)/ig; //@abc Match

How could I use a / instead of the # . I've tried doing var slash = '/' and adding + slash + , but that failed.

Answer 1

You can escape it like this.

/\//ig; //  Matches /

or just use indexOf

if(str.indexOf("/") > -1)

Answer 2

您需要使用\\来对/进行转义。

/\//ig // matches /

Answer 3

如果要使用/ ，则需要使用\\对其进行转义

var word = /\/(\w+)/ig;

Answer 4

In regular expressions, "/" is a special character which needs to be escaped (AKA flagged by placing a \\ before it thus negating any specialized function it might serve).

Here's what you need:

var word = /\/(\w+)/ig; //   /abc Match

Read up on RegEx special characters here: http://www.regular-expressions.info/characters.html

Answer 5

You can also work around special JS handling of the forward slash by enclosing it in a character group, like so:

const start = /[/]/g;
"/dev/null".match(start)     // => ["/", "/"]

const word = /[/](\w+)/ig;
"/dev/null".match(word)      // => ["/dev", "/null"]

Answer 6

For me, I was trying to match on the / in a date in C#. I did it just by using (\\/) :

string pattern = "([0-9])([0-9])?(\/)([0-9])([0-9])?(\/)(\d{4})";
string text = "Start Date: 4/1/2018";

Match m = Regex.Match(text, pattern);

if (m.Success) 
{ 
    Console.WriteLine(match.Groups[0].Value);  // 4/1/2018
}
else
{
    Console.WriteLine("Not Found!");
}

JavaScript should also be able to similarly use (\\/) .

Answer 7

I encountered two issues related to the foregoing, when extracting text delimited by \\ and / , and found a solution that fits both, other than using new RegExp , which requires \\\\\\\\ at the start. These findings are in Chrome and IE11.

The regular expression

/\\(.*)\//g

does not work. I think the // is interpreted as the start of a comment in spite of the escape character. The regular expression (equally valid in my case though not in general)

/\b/\\(.*)\/\b/g

does not work either. I think the second / terminates the regular expression in spite of the escape character.

What does work for me is to represent / as \\x2F , which is the hexadecimal representation of / . I think that's more efficient and understandable than using new RegExp , but of course it needs a comment to identify the hex code.

Answer 8

Forward Slash is special character so,you have to add a backslash before forward slash to make it work

$patterm = "/[0-9]{2}+(?:-|.|\/)+[a-zA-Z]{3}+(?:-|.|\/)+[0-9]{4}/";

where / represents search for / In this way you

Answer 9

You can escape it by preceding it with a \\ (making it \\/ ), or you could use new RegExp('/') to avoid escaping the regex .

See example in JSFiddle .

'/'.match(/\//)            // matches /
'/'.match(new RegExp('/')  // matches /