404 when accessing Jersey app in Tomcat 7
Question
I am a newby in web development and I am struggling to create a simple rest web service using jersey, packed as an independent war file, to be deployed on tomcat 7.
I have followed this tutorial in order to create simple hello world restful web service. I have used intelij in order to create the war file (both war file and exploded version of it) and deployed them on the tomcat\\webapps folder.
When starting up the tomcat, I fail to access the url ( http://localhost:8080/rest/hello ) - getting 404.
Looking at the tomcat's logs, I can't find any exception or error, other then these next set of lines:
INFO: Scanning for root resource and provider classes in the packages:
sample
εαΘ 30, 2013 11:24:38 PM com.sun.jersey.api.core.ScanningResourceConfig logClasses
INFO: Root resource classes found:
class sample.Hello
εαΘ 30, 2013 11:24:38 PM com.sun.jersey.api.core.ScanningResourceConfig init
INFO: No provider classes found.
I have searched it a lot and tried to follow all solutions for this error but nothing worked.
I have the feeling that I missing something very basic, due to my newbi'ness. Any ideas what to search ? what am I missing ? it's a simple hello world app and I am exahuster and frustrated...
Java class
package sample;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
@Path("hello")
public class Hello {
// This method is called if TEXT_PLAIN is requested
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayHelloInPlainText() {
return "Hello world!";
}
// This method is called if HTML is requested
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHelloInHtml() {
return "<html> " + "<title>" + "Hello world!" + "</title>"
+ "<body><h1>" + "Hello world!" + "</body></h1>" + "</html> ";
}
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>rest</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>sample</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
2 answers
solution1
7 ACCPTED 2013-06-01 11:16:09
This is similar to this SO question: " No provider classes found: when running Jersey REST example application ".
The message "No provider classes found" is fine, no need to worry about it. For the URL http://localhost:8080/rest/hello to work your WAR file needs to be called rest.war . Then rest becomes the context root. All the paths you define in the project's annotations are relative to the context root .
solution2
3 2013-06-01 11:02:22
if you have called your project in eclipse: rest, so you should get the correct message: "Hello world!" from tomcat with the url:
http://localhost:8080/rest/hello.
If you for example have called your project: MyHello, with the code you posted the correct url should be:
http://localhost:8080/MyHello/hello
(The reason is that Eclipse create by default a war called as the name of the project and publish it to the tomcat server you have added in your configuration)
Let me know
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