Thanks in advance for reading this, I couldn't find an answer that solved my problem... I don't understand what I'm doing differently than the tutorials/suggestions I found:
SQL Table
CREATE TABLE IF NOT EXISTS `LastInsertID` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` char(150) NOT NULL,
`email` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=6 ;
PHP File
<?php
// Connect to database
$user = "foo";
$pswd = "bar";
$db = new PDO( 'mysql:host=localhost;dbname=test', $user, $pswd );
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
// Prepare request
$rq = $db->prepare('INSERT INTO `LastInsertID` VALUES(NULL,:name,:email)');
// Begin and commit request
$db->beginTransaction();
$values = array('name'=>'Foo','email'=>'bar@baz.com');
$rq->execute($values);
$db->commit();
// Echo last ID
echo $db->lastInsertId();
?>
This returns 0 when it should return 6. Where is the problem?
You must use $db->lastInsertId()
before you commit if you are in a transaction. Even if you rollback a transaction, the id is "used" or skipped, which is why you should not depend on IDs to be sequential.
Use this
INSERT INTO `LastInsertID` (name, email) VALUES(:name,:email)
instead
INSERT INTO `LastInsertID` VALUES(NULL,:name,:email)
I have removed the NULL
.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.