Can't pass more than one argument using exec() PHP

Question

given the following code:

 exec('cmd /c c:\wamp\www\Telnetshutdown.py '.$router);

the router variable is passed fine. but, given the following code:

 exec('cmd /c c:\wamp\www\Telnetshutdown.py '.$router.' '.$interface);

or

 exec('cmd /c c:\wamp\www\Telnetshutdown.py '.$router." ".$interface);

or

         $zz=$router.' '.$interface;
 exec('cmd /c c:\wamp\www\Telnetshutdown.py '.$zz);

and more combinations of those.. Does not work! How can I pass more than one argument?

Answer 1

Try to use escapeshellarg to make sure your arguments are properly escaped

It appears also based on this post that php will frame the argument passed to exec with cmd /c "{{exec argument}}" when passing it off to the shell.

Try this:

exec('c:\wamp\www\Telnetshutdown.py '.escapeshellarg($router).' '.escapeshellarg($interface));