I have two controllers, homepage and Security.
In the homepage, I am displaying one view and in the security, I am doing some things, and one of them is the email address validation.
What I would like is that when the email validation code is not valid, display the homepage with a flash message. For that, I will have to render the indexAction of the HomepageController, from the Security controller, by giving him as parameter the flash message.
How can this be done? Can I render a route or an action from another controleller?
Thank you in advance.
I believe the checking should not be done in the Security controller. Right place in my opinion is a separate validator service or right in the entity which uses the email address.
But to your question, you can call another controller's action with $this->forward() method:
public function indexAction($name)
{
$response = $this->forward('AcmeHelloBundle:Hello:fancy', array(
'name' => $name,
'color' => 'green',
));
return $response;
}
The sample comes from symfony2 documentation on: http://symfony.com/doc/2.0/book/controller.html#forwarding
我找到了解决方案,只需通过指定控制器和动作nanme来使用forward函数:
return $this->forward('MerrinMainBundle:Homepage:Index', array('flash_message'=>$flash_message));
redirectToRoute : Just a recap with current symfony versions (as of 2016/11/25 with v2.3+)
public function genericAction(Request $request)
{
if ($this->evalSomething())
{
$request->getSession()->getFlashBag()
->add('warning', 'some.flash.message');
$response = $this->redirectToRoute('app_index', [
'flash_message' => $request->getSession()->getFlashBag(),
]);
} else {
//... other logic
}
return $response;
}
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