how to throw a 403 error in Apache CXF - Java

Question

I am using the following code based on having an interceptor. When check returns true I want to throw a 403 error:

    @Override
    public void handleMessage(Message arg0) throws Fault {


        HttpServletRequest request = context.getHttpServletRequest();
        if(check(request)){
        // currently not working
                throw "Fault";
        }

I want to throw a 403 error. How do I go about doing that from this situation?

I am a little confused about how "throws fault" works.

Any help is appreciated

Answer 1

CXF will default the status code to 500 for a Fault, but you can set it with Fault.setStatusCode . For example

Fault fault = new Fault(new Exception("Exception message"));
fault.setStatusCode(403);
throw fault;

Answer 2

Have you considered throwing:

throw new javax.ws.rs.ForbiddenException();

It returns http 403.