Using JS function with parameters in php

Question

The JS function is

function func(arg){  
    alert(arg);  
}

When I do

echo "<div onclick=\"func($arg)\">Text</div>";

in php, it doesnt work but when I do

echo "<div onclick=\"func()\">Text</div>";

it works and an alert with undefined text pops up.

How do I pass argument?

Answer 1

You need to quote the arguments. eg

<?php
$foo = 'bar';
?>

echo "function($foo) { ... }";

is going to produce the code

function(bar) { ... }

where bar will be interpreted as an undefined variable.

Safest method is to output your PHP variables via json_encode(), to guarantee you're producing syntactically valid javascript. eg

echo 'function(' . json_encode($foo) . ') { ... }';

which would produce (in this case)

function ('bar') { ... }

Answer 2

You need to wrap $arg in quotes. Example:

echo "<div onclick=\\"func('$arg')\\">Text</div>";

(using single quotes around arg as you're using double quotes for the string)

Answer 3

您可以这样做（如果$ args当然存在）

echo '<div onclick="func('.$arg.')">Text</div>';