NumPy random.shuffle function

Question

I ran into something strange with numpy.random.shuffle function

from numpy import arange
from numpy.random import shuffle

a = arange(5)
b = a
c = a[:]

shuffle(c)

a and b all changes with c . Actually no matter I shuffle() which variable, the other two all changes with it. I thought when I use slice copy the original variable should be independent. Did I miss something? How can I protect the original variable from being changed?

Answer 1

According to the Basic slicing documentation :

All arrays generated by basic slicing are always views of the original array.

Use ndarray.copy or numpy.copy to get copy.

Answer 2

使用c = a.copy()可以为您提供帮助。