Defining typescript generics with type safety

Question

Can you define generics with safe types, as you can with c#?

Eg

public bool Foo<T>() where T : struct { /* */ }

Typescript now has generics, but can I perform a similar action?

Thanks.

Answer 1

Ok it seems you can do this:

Foo<T extends IBar>() { /* */ }

And that seems to make all calls require the T to implement IBar .

Answer 2

如果您不想创建额外的类/接口，例如，您可以执行以下操作：

Foo<T extends{ id: string | number }>