I have two list:
a = [1, 2, 3, 4]
b = [5, 6, 7, 8]
I need to get something like this:
c = [1, 5, 2, 6, 3, 7, 4, 8]
I use this solution:
c = list(reduce(lambda x, y: x + y, zip(a, b)))
Is there a better way to do this?
Using List Comprehension :
>>> [x for tup in zip(a, b) for x in tup]
[1, 5, 2, 6, 3, 7, 4, 8]
The above nested list comprehension is equivalent to following nested for loops (Just in case you get confused):
result = []
for tup in zip(a, b):
for x in tup:
result.append(x)
Using chain
:
from itertools import chain, izip
interweaved = list(chain.from_iterable(izip(a, b)))
# [1, 5, 2, 6, 3, 7, 4, 8]
也可行:
list(sum(zip(a, b), ()))
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