here is the format of my regular expression:
@"^PR[a-zA-Z0-9-]{36}[0-9]{2}([a-zA-Z0-9-]{3}2[a-zA-Z0-9-]{12}){2,10}$"
.
There should be separate validation for each condition. So I succeeded for first three conditions using JavaScript sub-string. Just stuck for last condition ie
"([a-zA-Z0-9-]{3}2[a-zA-Z0-9-]{12}){2,10}"
.
In this, I want to check every fourth character must be "2".
How do i achieve this by JavaScript?
If you have the full regex, why not just use it as a whole:
var regex = /^PR[a-zA-Z0-9-]{36}[0-9]{2}([a-zA-Z0-9-]{3}2[a-zA-Z0-9-]{12}){2,10}$/;
var str = "PR12345678901234567890123456789012345600AAA2BBBCCCDDDEEEaaa2bbbcccdddeee";
console.log(regex.test(str)); // true
But if you must really break it, you could do:
var regex1 = /^PR[a-zA-Z0-9-]{36}$/;
console.log(regex1.test(str.substring(0,38))); // true
var regex2 = /^[0-9]{2}$/;
console.log(regex2.test(str.substring(38,40))); // true
var regex3 = /^([a-zA-Z0-9-]{3}2[a-zA-Z0-9-]{12}){2,10}$/;
console.log(regex3.test(str.substring(40,str.length))); // true
See demo fiddle here .
To check whether every fourth character must be two, use:
var regexfourth = /^([a-zA-Z0-9-]{3}2)+$/;
console.log(regexfourth.test("aaa2bbb2ccc2ddd2")); // true
console.log(regexfourth.test("aaa2bbb2ccc3ddd2")); // false(notice a 3 after ccc)
Demo fiddle for this here (check the bottom).
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