I have 2 table with the same field name and i want to display record from the two field columns.
Table_a
id date user test
1 2013-08-08 Adam Various
2 2013-08-08 Paul Record
Table_b
id date user test
1 2013-08-08 Adam Record
2 2013-08-08 Paul Mytest
$sql = "Select Table_a.date, Table_a.user, Table_a.test, Table_b.date, Table_b.user, Table_b.test FROM table_a, Table_b where Table_a.user like table_b AND table_a.Date = table_b.date AND table_b.Date = '".date("Y-m-d", strtotime("today"))."'";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
echo "<p'><b>" . $row['user'] . "</b></p>";
echo "<p><b>". $row['test'] ."</b></p>";
echo "<p><b>". $row['test'] ."</b></p>";
I want the result to be Adam -various -record for example.That is I want the third echo "<p><b>". $row['test'] ."</b></p>";
"<p><b>". $row['test'] ."</b></p>";
to display record from table_b.
Thanks
You can use SQL alias
SELECT column_name AS alias_name
Example from your code
$sql = "SELECT Table_a.date AS tableA_date,
Table_a.user AS tableA_user,
Table_a.test AS tableA_test,
Table_b.date AS tableB_date,
Table_b.user AS tableB_user,
Table_b.test AS tableB_test
FROM Table_a AS tableA,
Table_b AS tableB
WHERE tableA_user
LIKE tableB
AND tableA_date = tableB_date
AND tableD_date = '".date("Y-m-d", strtotime("today"))."'";
Try this:
$sql = "Select
a.date as adate,
a.user as auser,
a.test as atest,
b.date as bdate,
b.user as buser,
b.test as btest
FROM table_a a, Table_b b
where
a.user like b.user
AND a.Date = b.date
AND b.Date = '".date("Y-m-d", strtotime("today"))."'";
echo "<p'><b>" . $row['auser'] . "</b></p>";
echo "<p><b>". $row['atest'] ."</b></p>";
echo "<p><b>". $row['btest'] ."</b></p>";
Note that I have written a.user like b.user
. a.user like b
is wrong.
user the below query
Select table_a.user,table_a.test,table_b.test FROM table_a left join table_b on
table_a.user=table_b.user where table_a.Date = table_b.date AND table_b.Date = curdate()
it will return result like below
think it will solve your problem.
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