I have this SQL SELECT in PHP:
SELECT *
FROM ads
ORDER BY ad_sponsored_date DESC, ad_date DESC
I want to display a list of ads, they are normally sorted by date but if one is sponsored, then it appears in top. The above does that nicely; but I need to also test if that ad_sponsored_date is not grater than timestamp and if so, then only sort by the second one (ad_date) , is it possible?
Something like this but I don't know the correct syntax:
SELECT *
FROM ads
ORDER BY (ad_sponsored_date DESC IF ad_sponsored_date > $timestamp, ad_date DESC)
This captures your logic in SQL:
SELECT *
FROM ads
ORDER BY (case when ad_sponsored_date > $timestamp then ad_sponsored_date end) desc,
ad_date DESC;
I am, however, unclear on what to do for the "else" part of the if.
Note: in MySQL NULL values are placed last for a descending sort, which is why this puts the sponsored ads at the top of the list.
Try
SELECT *
FROM ads
ORDER BY CASE WHEN ad_sponsored_date > '$timestamp'
THEN ad_sponsored_date
ELSE ad_date END DESC
Here is SQLFiddle demo
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