I'm trying to parse a xml with the below content
<File version="5.6">
<Parent name="A">
<Child name="a"/>
<Child name="b"/>
</Parent>
<Parent name="B">
<Child name="c"/>
<Child name="d"/>
</Parent>
<Parent name="C">
<Child name="e"/>
<Child name="f"/>
</Parent>
</File>
And I used the following code
for child in tree.getroot().findall('./Parent/Child')
print child.attrib.get("name")
It just print all the name of children without the parent names. Can I print the relevant parent name of each child like this?
A has a b
B has c d
C has e f
Iterate over parents, then find children of the parents.
for parent in tree.findall('./Parent'):
children = [child for child in parent.findall('./Child')]
print '{} has {}'.format(parent.get('name'), ' '.join(c.get('name') for c in children))
Response to the comment
Using lxml, you can access parent node with getparent()
method.
import lxml.etree
tree = lxml.etree.parse('1.xml')
for child in tree.findall('./Parent/Child'):
print '{} has {}'.format(child.getparent().get('name'), child.get('name'))
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