I want to add
I read its not easy to make such jar :( and there is no fool prroof way...
I have tried searching for it on net and found I will have to create URL and then file and then use it... however, when I use below code, I am not able to get URL itself...
URL urlOfDraftInSamePackage = CreateDraft.class.getResource("Draft_in_same_package.docx");
System.out.println("urlOfDraftInSamePackage is "+urlOfDraftInSamePackage.toString());
//This prints : urlOfDraftInSamePackage is file:/D:/aditya_workspace/SampleDraftMaker/bin/draftProcessing/Draft_in_same_package.docx
URL urlOfDraftInResourceFolder = CreateDraft.class.getResource("resouces/Draft_Apartment.docx");
System.out.println("urlOfDraftInResourceFolder is "+urlOfDraftInResourceFolder.toString());
//this gives null pointer exception
URI uri = null;
try {
uri = urlOfDraftInSamePackage.toURI();
File file = new File(uri);
System.out.println("file made");
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
below is my folder structure:
can anyone pls help me in creating such executable jar using eclipse?
Thanks In Advance!!!
Following code works for me:
public static void testResource() throws IOException {
InputStream stream = Deserializace.class.getResourceAsStream("resources/ser.log");
BufferedReader reader = new BufferedReader(new InputStreamReader(stream));
String s;
while ( (s = reader.readLine()) != null) {
System.out.println(s);
}
}
Build directory structure:
Test.class
resources/ser.log
You must ensure that your resource directory is copied to correct place.
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