how to do simple concat in awk in mac

Question

So I have a file list.txt similar to this one:

                              186
                              423
                              423
                              234
                              634
                              437

And I want an output similar to this:

SET 186 0
SET 423 0
SET 423 0
SET 234 0
SET 634 0
SET 437 0

I tried with this:

sed 's/^ *//g' list.txt | awk '{a="SET ";b=" 0";print a,$0,b}'

But it prints

  0 186
  0 423
  0 423
  0 234
  0 634
  0 437

Given that

sed 's/^ *//g' list.txt | awk '{a="SET ";b=" 0";print a,$0}'

Works perfect:

SET 186
SET 423
SET 423
SET 234
SET 634
SET 437

So I don't know what I'm doing wrong.

Do you know how to solve this and why print a,$0,b doesn't work?

Answer 1

It doesn't work because your input file was created on Windows and so has spurious control-Ms at the end of each line and that's messing up the displayed output. Run dos2unix on the file or otherwise get rid of those control-Ms and your script would work as written, but a better way to do it would be simply:

awk '{print "SET",$1,0}' list.txt

Answer 2

使用awk，其：

awk '{printf "SET %d 0\n", $1}' your.file

Answer 3

Simply:

$ awk '{print "SET",$1,0}' file
SET 186 0
SET 423 0
SET 423 0
SET 234 0
SET 634 0
SET 437 0

Answer 4

try this awk one-liner:

awk '$0="SET "$1" 0"' file

outpus:

SET 186 0
SET 423 0
SET 423 0
SET 234 0
SET 634 0
SET 437 0

Answer 5

awk '{print "SET", $1, "0"}' file

Answer 6

This sed with inline switch -i works:

sed -i.bak 's/\([0-9]*\)/SET \1 0/' file

-i.bak will make sure to save changes into the file with backup created with .bak extension.