I have a table eg
Artist Title Song Key
A Title A A
A Title A B
A Title A F
B Title B A
I want to return each individual song but also show how many versions there are of that song eg Ideal results would be:
Artist Title How_many
A Title A 3
B Title B 1
This is what I'm trying but the count counts all tracks and not just from the current line:
SELECT *,
( select count(*)
from tracks
where artist=artist
AND title=title ) as How_many
from tracks
where easytosing='Yes'
group by title, artist
order by track_id desc
Is this possible using a nested query or is there a better way?
try this:
SELECT Artist, title, count(*) as How_many
FROM tracks
WHERE easytosing='Yes'
GROUP BY Artist,Title
SELECT t.*, how_many
from tracks t
inner join
( select title,artist, count(*) ,how_many
from tracks
group by artist,title ) as temp
temp.title=t.title and temp.artist=t.artist
where easytosing='Yes'
SELECT Artist,Title, COUNT(*) FROM TABLE1 GROUP BY Artist,Title
Just simply you can execute the following query with group by
select Artist,Title,count(Song_Key) as How_many
from Tracks
group by Artist,Title
once you execute above query you will get the result as you like.
ARTIST TITLE HOW_MANY
A Title A 3
B Title B 1
2 rows returned in 0.00 seconds
In the specific case:
SELECT title, artist, count(*)
from tracks
where easytosing='Yes'
group by title, artist
because you get for every artist / title the number of songs.
You don't need of subquery in this case.
Another query you can perform is a query where the main select is based on disk table (I think you have a disk table where you have a foreign key at the artist and a name of your disk) where you get a number of contained song for each artist / disk.
In this way if there are no songs for one disk you get zero value.
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