Dev-C++: 'prinft' undeclared

Question

I´m completely new to programming and just started some tutorials from the internet. One of them suggested this code for an easy question for the user:

#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
int input;

printf("Please enter a number between 1 and 4:\n");
scanf("%d",&input);
fflush(stdin);

switch(input)
{
case 1: prinft("You entered 1\n");
break;
case 2: prinft("You entered 2\n");
break;
case 3: printf("You entered 3\n");
break;
case 4: printf("You entered 4\n");
break;
default: printf("Unknown Input, please try again\n");
}

system("PAUSE");
return 0;
}

I use Dev-C++ and can´t even compile the code. the "case 1:"-row gets highlighted and the error-message says: 'printf' undeclared (first use this function). Can anybody tell me how to fix this problem?

Answer 1

Typo:

prinft()

should be:

printf()

printf is short for "print formatted".

Answer 2

Small mistakes in your code can confuse you, but you got to be persistent. This community, is generally harsh to beginners. Anyway, best of wishes in you programming adventures.

prinft(); 

should actually be

printf();

Some advice: you can change int main(int argc, char *argv[]) to

int main(int a, char *b[]) and whatever else you want. You don't have to confuse yourself.