Comparing two numbers without loops or branching in Python

Question

I have to compare two numbers and write greater, then smaller, but I don't know how to get smaller one. I currently have this code:

a = int(input())
b = int(input())
c = round(((a + b) + abs(a - b)) / 2)
x = "should be smaller one"
print("{0}\n{1}".format(c, x))

Answer 1

较小的是： c = round(((a + b) - abs(a - b)) / 2)

Answer 2

If I right understand you:

In [1]: a , b = 3, 4

In [2]: smaller = a if a < b else b

In [3]: smaller
Out[3]: 3

Here you can replace < to other operator