Passing addresses of variables into other functions

Question

Okay, if I declare/initialize a variable, and then pass it's address to another function, is that the same as saying int* n = &i ? In other words, is the act of passing the address to another function itself CREATING a pointer? I almost wanna say to myself "yes, duh, that's a stupid question" but I just want to make sure that I am understanding this correctly.

foo(int* n) {
    //do something
}


main () {
  int i = 5;
  foo(&i);
}

Answer 1

是的，您的假设是正确的，变量int * n本身具有一个唯一的地址，您可以使用＆n获取该地址