So I am basically trying to open and close a batch file (that runs a minecraft server) at specific times. The thing that is bothering me though is that when the file opens it does so in the same window as my script and therefore basically stops my code which consiquently means that the file will have to be manually closed. I was wondering if there is a way to open it in a separate window. This is thd code I have so far:
import os
import time
print "updates ever 15 mins = 0.25 hours"
hours = input("Current time (nearest 0.25 hour): ")
x = input("Opening time (hour): ")
y = input("Closing time (hour): ")
os.system ("cls")
os.chdir ("C:\\Users\\USERNAME\\Desktop\\Server")
while True:
os.system("cls")
time.sleep(900)
hours += 0.25
difx = x - hours
dify = y - hours
if difx == 0:
os.popen("run.bat")
if dify == 0:
os.system ("say CLOSING in 10 SECONDS")
time.sleep (10)
os.system ("stop")
os.system ("taskkill /f /im cmd.exe")
if hours == 25:
hours = 1
stop is a command that stops the server running and saves all the info but leaves the window open (hence the taskkill command). Any help would be much appreciated.
将os.popen(“ run.bat”替换为os.startfile(“ filepath \\ run.bat”)应该可以。(谢谢)
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