Why does every object in Java implicitly extend java.lang.Object class?

Question

I have been programming in Java for quite some time, but when I tried to explain what an java.lang.Object class is to a friend, I could not come up with more than a simple one-liner:

All objects in Java extend java.lang.Object implicitly

I was not quite sure why it should do so.

So, I looked upon the source code on GrepCode , hoping that I can find some clues. Now I know what a java.lang.Object is and what it does, I want to know if there was any specific reason as to why it was designed this way.

My question still prevails: why should every object extend java.lang.Object ?

Answer 1

I would say that the reason is to have a common API for all objects in java to supports basic functionality like

• synchronization - wait , notify , notifyAll
• garbage collection - finalize
• collection support - hashCode , equals
• object cloning - clone

And every object

• has a class it belongs to - getClass
• can represent itself as a string, because we are humans and can read strings - toString

Answer 2

This is how the language is designed. Every object will inherit from the base class Object . This means that it's guaranteed for every object there will be certain methods, like toString() , equals() , hashCode() , etc.

Answer 3

I think the most important use of Object is not to provide common methods like toString() but to provide a common type that would hold all reference types.

C++ don't have an Object equivalent and people are still happy. But since Java don't have pointers and C++-like templates, Object is required to make implementations of Collection s, etc. possible.

See also on discussions on reference and primitive types.

Answer 4

I would say Design . Common/Mandatory methods which every Object should support written there and extending that class as a language specification.

You find the reasons here in Official Docs .

If we are saying this is an Object ,They must have the common methods, Which defined/decided by API .

Imagine the below methods for every class on your Own.

protected Object clone() throws CloneNotSupportedException
      Creates and returns a copy of this object.


public boolean equals(Object obj)
      Indicates whether some other object is "equal to" this one.


protected void finalize() throws Throwable
      Called by the garbage collector on an object when garbage
      collection determines that there are no more references to the object


public final Class getClass()
      Returns the runtime class of an object.


public int hashCode()
      Returns a hash code value for the object.


public String toString()
      Returns a string representation of the object.

The notify, notifyAll, and wait methods of Object all play a part in synchronizing the activities of independently running threads in a program:

public final void notify()
public final void notifyAll()
public final void wait()
public final void wait(long timeout)
public final void wait(long timeout, int nanos) 

So to reduce the pain, created a common and standard API .

Answer 5

这样做是因为像toString（）等大多数基本函数都会被自动继承而且你的下一个问题是多重继承它是继承...在单个类是从2个或更多基类派生的在多级中，如你所说它有一个基类，它本身派生自Object类

Answer 6

Every Class extends Object class implicitly so that they provide basic features which according to Java recommendation every class should have. Such as clone(), equals(), hashCode(), toString(), etc.

By implicitly, it means that if you are not extending any class then only compiler will implicitly extends Object class.But if class already extends other class then compiler will not extend Object class. For eg. Class A{ }

Class B extends A{ }

Here compiler will implicitly add extends Object class in class A declaration.

Class A extends Object { }

Class B extends A{ }

As class A extends Object class so it will provide basic functionality of Object class such as equals(), toString(),etc. And since Class B extends class A which implicitly extends Class Object, so class B also provides all those features.

Thus by following this approach every class objects(variables) complies to features which every Java Object should have, without going for Multiple Inheritance (a class extending more than one class) which Java doesn't allows. This approach follows Multi-Level Inheritance.

Answer 7

See the docs :

The Object class, in the java.lang package, sits at the top of the class hierarchy tree. Every class is a descendant, direct or indirect, of the Object class. Every class you use or write inherits the instance methods of Object. You need not use any of these methods, but, if you choose to do so, you may need to override them with code that is specific to your class.

The Object class simply defines the basic state that all objects must have - Like comparing it to other objects.

It's the parent class of everything. It simply provides kind of template to all the derived objects.

Answer 8

It's a java design decision. It puts to use the concept of inheritance and re-usabilty. This ensures that all classes have some basic methods like wait() , toString() etc.

Answer 9

Object class is the most super class of java programming, It has predefined methods according to types, you can use those methods. & you don't need to extends object class anymore & anywhere it's implicitly there

Answer 10

Quoting Head first Java 2nd edition:

Without a common superclass for everything in Java, there'd be no way for the developers of Java to create classes with methods that could take your custom types... types they never knew about when they wrote the ArrayList class.

Which essentially explains the need of a generic predefined class type in Java, which can be used to implement the different features provided by the language.