How to know if a page is called via a POST method in PHP.
Question
I am using the following code in order to modify the database using PHP:
<?php
//connect to the database
$connect = mysql_connect("localhost","root","");
mysql_select_db("loginform",$connect); //select the table
//
if ($_FILES['csv']['size'] > 0) {
//get the csv file
$file = $_FILES['csv']['tmp_name'];
$handle = fopen($file,"r");
//loop through the csv file and insert into database
do {
if ($data[0]) {
mysql_query("INSERT INTO mytable( name,country,age) VALUES
(
'".addslashes($data[0])."',
'".addslashes($data[1])."',
'".addslashes($data[2])."'
)
");
}
} while ($data = fgetcsv($handle,1000,",","'"));
//
//redirect
header('Location: sample.php?success=1'); die;
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Import a CSV File with PHP & MySQL</title>
</head>
<body>
<?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?>
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
Choose your file: <br />
<input name="csv" type="file" id="csv" />
<input type="submit" name="Submit" value="Submit" />
</form>
</body>
</html>
I am able to insert the data in to MySQL table but the problem is I am getting an error:
Notice: Undefined index: csv in C:\xampp\htdocs\deepthi\excel\sample.php on line 8
Notice: Use of undefined constant success - assumed 'success' in C:\xampp\htdocs\deepthi\excel\sample.php on line 44
I think it is because while the page is loading without a postback even then the code is executing. How to check that page is loaded via a Submit button click? Can someone help me?
5 answers
solution1
2 2013-10-03 09:13:26
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
echo "Page is called via a POST method";
}
solution2
1 2013-10-03 08:45:29
Use the following code just before your if statement
if($_SERVER['REQUEST_METHOD'] == 'POST')
The above code indicates that the page request came from a submit button. (of POST type)
eg:
<?php
//connect to the database
$connect = mysql_connect("localhost","root","");
mysql_select_db("loginform",$connect); //select the table
//
if($_SERVER['REQUEST_METHOD'] == 'POST')
if ($_FILES['csv']['size'] > 0) {
//get the csv file
$file = $_FILES['csv']['tmp_name'];
$handle = fopen($file,"r");
//loop through the csv file and insert into database
do {
if ($data[0]) {
mysql_query("INSERT INTO mytable( name,country,age) VALUES
(
'".addslashes($data[0])."',
'".addslashes($data[1])."',
'".addslashes($data[2])."'
)
");
}
} while ($data = fgetcsv($handle,1000,",","'"));
//
//redirect
header('Location: sample.php?success=1'); die;
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Import a CSV File with PHP & MySQL</title>
</head>
<body>
<?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?>
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
Choose your file: <br />
<input name="csv" type="file" id="csv" />
<input type="submit" name="Submit" value="Submit" />
</form>
</body>
</html>
solution3
0 ACCPTED 2013-10-03 08:46:10
Your variable is not having value and you are accessing it. Please update
if ($_FILES['csv']['size'] > 0) {
To,
if (isset($_FILES['csv']['size'])) {
if ($_FILES['csv']['size'] > 0) {
Also, add closing brace }
Your success is a key of array, it should be enclosed by commas( ' ). And also change:
<?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?>
to
<?php if (isset($_GET['success']) && !empty($_GET['success'])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?>
solution4
0 2013-10-03 09:01:43
As Sunny Gupta says,
check the method : if the form has been submitted (the submit button clicked), then $_POST is set. You want to process $_FILES only is this is the case
sidenote 1 : using unquoted indexes for arrays triggers warnings and logs. That's, in the best case, useless. Consider using quotes instead of non existing PHP constants :
if (!empty($_GET['success']))
sidenote 2 : your do/while will always log an error on the first loop. Prefer clean code and initialize $data before using it, not after. Also, don't check only $data[0] if you want to read 3 entries.
while ($data = fgetcsv($handle,1000,",","'")) { if (count($data) > 2) { [...] } } ;
sidenote 4 : last but not least, mysql_xxx functions are deprecated. Consider using mysqli_xxx functions instead. And prefer mysqli_real_rescape_string to addslashes() , it's safer.
solution5
0 2013-10-03 09:27:09
POST Statement Check
if((isset($_POST['Submit']) && trim($_POST['Submit']) == "Submit") && ($_SERVER['REQUEST_METHOD'] == 'POST'))
<?php
//connect to the database
$connect = mysql_connect("localhost","root","");
mysql_select_db("loginform",$connect); //select the table
//
if((isset($_POST['Submit']) && trim($_POST['Submit']) == "Submit") && ($_SERVER['REQUEST_METHOD'] == 'POST'))
{
if ($_FILES['csv']['size'] > 0)
{
//get the csv file
$file = $_FILES['csv']['tmp_name'];
$handle = fopen($file,"r");
//loop through the csv file and insert into database
do {
if ($data[0]) {
mysql_query("INSERT INTO mytable( name,country,age) VALUES
(
'".addslashes($data[0])."',
'".addslashes($data[1])."',
'".addslashes($data[2])."'
)
");
}
} while ($data = fgetcsv($handle,1000,",","'"));
//
//redirect
header('Location: sample.php?success=1'); die;
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Import a CSV File with PHP & MySQL</title>
</head>
<body>
<?php if (!empty($_GET[success])) { echo "<b>Your file has been imported.</b><br><br>"; } //generic success notice ?>
<form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
Choose your file: <br />
<input name="csv" type="file" id="csv" />
<input type="submit" name="Submit" value="Submit" />
</form>
</body>
</html>
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