storing awk results to bash ${} data format

Question

i got a question about bash and awk, so, i'm going to filter the processes list from ps aux then i did filtering by grep , then i filter it again using awk to display only the pid and the path of the process, then save it to the corresponding ${pid} and ${path} field. the question is, when i done filtering the results using awk, i'm going to save those results on ${pid} for pid numbers and ${path} for process's path, but i got no idea at all on doing that thing. if anyone here have a solution it would be very appreciated.

Thanks

EDIT: here is the code

ps aux | grep 'firefox' | awk '{print $2 " " $11}'

then i don't know what to do to save the $2 content to ${pid} and $11 to ${path} and save those fields to the txt file again...

Answer 1

应该这样做：

read pid path <<< $(ps aux | grep 'firefox' | awk '{print $2 " " $11}')

Answer 2

If all else fail remember that you have the disk that you can use. Pipe the result to a file and then process the file using awk or cut two times to assign the fields to the corresponding variables.

For example:

$result > tmp
pid=`cat tmp | cut -f 1`
path=`cat tmp | cut -f 2`
rm tmp

Answer 3

use set :

out=$(ps aux | grep 'nginx' | awk '{print $2 " " $11}' )
set $out
pid=$1
path=$2
echo $pid
echo $path

Answer 4

awk_output=($(ps aux | awk '/firefox/{print $2, $11}'))
pid="${awk_output[0]}"
path="${awk_output[1]}"

If your paths can contain spaces you'll need a different solution involving setting IFS.