Trying to run a program in C

Question

Can someone help me to run this program? I tried this:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(void) {
    double Cateto1;
    double Cateto2;
    double hipotenusa;

    printf("dame el primer cateto: ");
    scanf("%1f", Cateto1);
    fflush(stdout);

    printf("dame el segundo cateto: ");
    scanf("%1f", &Cateto2);
    fflush(stdout);

    hipotenusa = sqrt ((Cateto1*Cateto1)+(Cateto2*Cateto2));

    printf("hipotenusa= %2f",hipotenusa);
    system("pause");
}

I can build it but I can't run it... it gives me:

RUN FAILED (exit value -1.073.741.790, total time: 17s)

Answer 1

scanf("%lf", Cateto1);
        ↑    ↑
        |    You are missing a '&' character here
        The width specifier for doubles is l, not 1

The first argument to scanf must be "%lf" (as the letter L) to specify that the corresponding output variable is a pointer to double instead of a float. '1' (One) has no meaning for scanf.

The second argument to scanf here is expected to be a pointer to double, and you're giving it a double instead.
I suppose it is a simple typo since you got it right the second time.

Answer 2

Here is the mistake:

scanf("%1f", Cateto1);

Change it to:

scanf("%1f", &Cateto1);

Answer 3

There is an Error in your code. Instead of

scanf("%1f", Cateto1);

you should write:

scanf("%1f", &Cateto1);

Answer 4

简单的错误

scanf("%1f", &Cateto1); // '&' was missing in all scanf statements

Answer 5

             #include <stdio.h>

             #include <math.h>

            int main(void) 
            {

               double Cateto1;

               double Cateto2;

               double hipotenusa;

               printf("dame el primer cateto: ");

               scanf("%lf", &Cateto1);

               //fflush(stdout);

               printf("dame el segundo cateto: ");

               scanf("%lf", &Cateto2);

               //fflush(stdout);

               hipotenusa = sqrt ((Cateto1*Cateto1)+(Cateto2*Cateto2));

               printf("hipotenusa= %2f\n",hipotenusa);

               //system("pause");

               return 0;

         }

Answer 6

There are a couple of errors:

• The syntax of the scanf expression was wrong: "%1f" should be "%lf"
• You need to pass the address of Cateto1 ( &Cateto1 ) to scanf
• You don't need the fflush
• You don't need the system call

Here's the updated code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(void) {
    double Cateto1;
    double Cateto2;
    double hipotenusa;

    printf("dame el primer cateto: ");
    scanf("%lf", &Cateto1);

    printf("dame el segundo cateto: ");
    scanf("%lf", &Cateto2);

    hipotenusa = sqrt ((Cateto1*Cateto1)+(Cateto2*Cateto2));

    printf("hipotenusa= %2f\n",hipotenusa);
}