Datetime and SELECT * FROM table WHERE date = TODAY

Question

The column (date) in the database says "2013-10-14 14:37:38" for example.

How can I edit $todaysDate to display ALL dates today? I know that I have to use % somewhere but I have tried a lot of ways without success. :/

My code is below:

$todaysDate = date("Y-m-d");

$query_today = $db->prepare("SELECT * FROM table WHERE date=:date");
$query_today->bindParam(":date", $todaysDate);
$query_today->execute();

UPDATE Nothing below is working. I just want to select all dates in the database from a simple date("Ymd") . If the date is "2013-10-14 14:37:38" in the database I want to select it with just 2013-10-14. Something like date("Ymd%") .

Answer 1

Example, if you will search other dates beside today:

$todaysDate = date("Y-m-d"); # or any other date
$query_today = $db->prepare("SELECT * FROM table WHERE DATE(date) = :date");
$query_today->bindParam(":date", $todaysDate);
$query_today->execute();

Example, only for current date:

$query_today = $db->prepare("SELECT * FROM table WHERE DATE(date) = CURDATE()");
$query_today->execute();

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ps but like @ypercube said, if you have index on date field, his example will use that index.

$todaysDate = date("Y-m-d");
$query_today = $db->prepare("SELECT * FROM table WHERE date >= :date AND date < DATE_ADD(:date, INTERVAL 1 DAY)");
$query_today->bindParam(":date", $todaysDate);
$query_today->execute();

or

$query_today = $db->prepare("SELECT * FROM table WHERE date >= CURDATE() AND date < DATE_ADD(CURDATE(), INTERVAL 1 DAY)");
$query_today->execute();

Answer 2

This will work whether the column is of type DATE , DATETIME or TIMESTAMP and will use an index, if there is one available:

WHERE date >= CURRENT_DATE
  AND date < CURRENT_DATE + INTERVAL 1 DAY

Answer 3

A simple

SELECT * FROM table WHERE date = DATE(NOW())

should suffice.

Or as Alma pointed out,

SELECT * FROM table WHERE date = CURDATE()

Answer 4

Instead of below code:

$query_today = $db->prepare("SELECT * FROM table WHERE date=:date");

Use the following code:

$query_today = $db->prepare("SELECT * FROM table WHERE DATE_FORMAT(date, '%Y-%m-%d')=:date");

Answer 5

$query_today = $db->prepare("SELECT * FROM table WHERE DATE(date)=DATE(:date)");