Windows Forms equivalent of WPFs OnStartup event

Question

protected override void OnStartup(StartupEventArgs e)

I want the equivalent of this event for Windows Forms.

I'm making a image viewing application. My application is one of the default programs that opens a .JPG. So how can i get the path of the file

Answer 1

In the file Program.cs , there should be following method:

static void Main(string[] args)

args contains the parameters passed to your application, eg the file that should be opened.

Answer 2

If you just need the path of the file started the process you can go about this

var path = Assembly.GetEntryAssembly().Location;

To get the path of file association clicked you need to look at the command line args

var pathOfFileAssociation = Environment.GetCommandLineArgs()[1] ;

Answer 3

You can do it like this:

private void Form1_Load(object sender, System.EventArgs e)
{
    //this gives you the path of the executing assembly
    MessageBox.Show(System.IO.Path.GetDirectoryName(Application.ExecutablePath));
}