Play framework 2.1.3 function that will render scala template with given parameters

Question

I need a method in my controller to call the appropriate template, from the parameters that it received, in this manner:

public static Result renderTemplate(String folder, String template) {
    return ok(
        views.html.<<FOLDER_GOES_HERE>>.<<TEMPLATE_NAME_GOES_HERE>>.render(Users.createForm)
    );
}

if this possible? I would have done it with reflection, but for some reason I can't list the fields of view and view.html.

Can someone tell me why and explain what should I do to accomplish this?

Thank you

Answer 1

If you go that way you may loose type safety and the possebility to catch some error on on compile time instead of runtime.

But is still possible:

final Class<?> clazz = Class.forName("views.html." + folder + "." + template);
//assumed you have a String parameter for your template
java.lang.reflect.Method render = clazz.getDeclaredMethod("render", String.class);
play.api.templates.Html html = (play.api.templates.Html) render.invoke(null, "hi");
return ok(html);

Another way that does no include the overhead of reflection is to make an index of the templates at build time with SBT and source generators . You can walk through the views folder and then create a map from folder/template name and the invokations.

The map is in a generated class and looks like this:

map.put("folderx.templatey", views.html.folderx.templatey);//no reflection!

So at least SBT warns you at build time if the template does not exist.