How to return the pointer in a pointer in a pointer

Question

I feel like this should be very easy, but I am unable to find an applicable question.

X is a shared_ptr<shared_ptr<Item> > .

I have a function that accepts a shared_ptr<Item>

How do I get that inner pointer? I can't just do X -> , and X->get() will return an Item*

Answer 1

与普通指针一样，可以通过取消引用共享指针的目标来访问它：

f(*X);